From the Periodic table, it can be determined that iron (Fe) has an atomic mass of 56 amu, oxygen (O) has an atomic mass of 16 amu, and hydrogen (H) has a mass of 1 amu. What would the atomic mass of Fe(OH)3
be?(1 point)
Responses
75 amu
75 amu
73 amu
73 amu
107 amu
107 amu
219 amu
To calculate the atomic mass of Fe(OH)3, we first need to determine the atomic mass of each element in the compound.
Fe = 56 amu (given)
O = 16 amu (given)
H = 1 amu (given)
Next, we multiply the atomic mass of each element by the number of atoms present in the compound.
Fe(OH)3 contains:
- 1 Fe atom
- 3 O atoms
- 3 H atoms
Fe = 1 x 56 amu = 56 amu
O = 3 x 16 amu = 48 amu
H = 3 x 1 amu = 3 amu
Finally, we add up the atomic masses of each element to find the total atomic mass of Fe(OH)3.
56 amu + 48 amu + 3 amu = 107 amu
Therefore, the atomic mass of Fe(OH)3 is 107 amu.
To calculate the atomic mass of Fe(OH)3, we need to multiply the atomic mass of each element by its respective subscript and then add them together.
The atomic mass of Fe is 56 amu.
The atomic mass of O is 16 amu.
The atomic mass of H is 1 amu.
In Fe(OH)3, we have:
1 Fe atom
3 O atoms
3 H atoms
Therefore, the atomic mass of Fe(OH)3 can be calculated as follows:
(1 Fe atom * 56 amu) + (3 O atoms * 16 amu) + (3 H atoms * 1 amu) = 56 amu + 48 amu + 3 amu = 107 amu.
So, the correct answer is 107 amu.