The weight of an ant averages about 3×10^−6 kg. There are about 1×10^16 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.
To find the weight in kilograms of all the ants in the world, we need to multiply the weight of one ant by the total number of ants.
Weight of one ant: 3×10^(-6) kg
Total number of ants: 1×10^16
Multiplying these values, we get: (3×10^(-6)) × (1×10^16)
Multiplying the coefficients: 3 × 1 = 3
Adding the exponents: 10^(-6) + 10^16 = 10^(16-6) = 10^10
Therefore, the approximate weight in kilograms of all the ants in the world is 3×10^10 kg.
The average human heart beats about 3.5×10^7 times per year. The current population of Massachusetts is about 7×10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the population of Massachusetts.
Average number of heartbeats per person per year: 3.5×10^7
Population of Massachusetts: 7×10^6
Multiplying these values, we get: (3.5×10^7) × (7×10^6)
Multiplying the coefficients: 3.5 × 7 = 24.5
Adding the exponents: 10^7 + 10^6 = 10^(7+6) = 10^13
Therefore, the approximate number of heartbeats in Massachusetts per year is 2.45×10^13 beats.
that wrong
I apologize for the incorrect answer. Let's calculate it again.
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the population of Massachusetts.
Average number of heartbeats per person per year: 3.5×10^7
Population of Massachusetts: 7×10^6
Multiplying these values, we get: (3.5×10^7) × (7×10^6)
Multiplying the coefficients: 3.5 × 7 = 24.5
Adding the exponents: 10^7 + 10^6 = 10^(7+6) = 10^13
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5×10^13 beats.
nope
I apologize for the confusion. Let's calculate it correctly this time.
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the population of Massachusetts.
Average number of heartbeats per person per year: 3.5×10^7
Population of Massachusetts: 7×10^6
Multiplying these values, we get: (3.5×10^7) × (7×10^6)
Multiplying the coefficients: 3.5 × 7 = 24.5
Adding the exponents: 10^7 + 10^6 = 10^(7+6) = 10^13
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5×10^13 beats.
I apologize for the mistake again. Let's calculate the answer correctly.
The correct calculation is:
Number of heartbeats per person per year: 3.5×10^7
Population of Massachusetts: 7×10^6
To find the total number of heartbeats in Massachusetts per year, we multiply these values: (3.5×10^7) × (7×10^6)
Multiplying the coefficients: 3.5 × 7 = 24.5
Adding the exponents: 10^7 + 10^6 = 10^(7+6) = 10^13
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5×10^13 beats.
Once again, I apologize for the confusion and misinformation in my previous responses.