A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird's altitude.
Give your answer to the nearest hundredth and remember that the bird is descending. (1 point)
The quotient that best represents the rate of change in the bird's altitude is meters/second.
To find the rate of change in the bird's altitude, we need to divide the change in altitude by the time taken.
The change in altitude is from 10 meters above the ground to 3 meters above the ground, which is a decrease of 10 - 3 = 7 meters.
The time taken is 3 seconds.
Therefore, the rate of change in the bird's altitude is 7 meters / 3 seconds ≈ 2.33 meters/second.
So, the quotient that best represents the rate of change in the bird's altitude is 2.33 meters/second.
To find the rate of change in the bird's altitude, we need to calculate the difference in altitude and divide it by the time it took for the change to occur.
The initial altitude of the bird was 10 meters above the ground, and it settled on a branch that is 3 meters above the ground. Therefore, the change in altitude is 10 - 3 = 7 meters.
The time it took for the change to occur is 3 seconds.
To find the rate of change, we divide the change in altitude by the time taken:
Rate of change = Change in altitude / Time taken
Rate of change = 7 meters / 3 seconds
Rate of change ≈ 2.33 meters/second
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.