What number can you subtract from 3200 so that their differences can give a 4digit number that has: the digit 2 in the thousands place, the digit 3 in the hundreds place and zeros in the tens and ones place?
To find the number that can be subtracted from 3200 to give a 4-digit number with the given conditions, we need to find a number that has a 2 in the thousands place, a 3 in the hundreds place, and zeros in the tens and ones place.
The four-digit number we are looking for can be expressed as 2000 + 300 + 0 + 0 = 2300.
So, to find the number that can be subtracted from 3200 to give us 2300, we subtract 2300 from 3200:
3200 - 2300 = 900
Therefore, the number that can be subtracted from 3200 to give us a 4-digit number with a 2 in the thousands place, a 3 in the hundreds place, and zeros in the tens and ones place is 900.
To find out the number that can be subtracted from 3200 to obtain a 4-digit number satisfying the given conditions, we can set up the equation:
3200 - x = 2300
Where x is the number we want to find.
Now we solve for x:
3200 - x = 2300
-x = 2300 - 3200
-x = -900
To solve for x, we can multiply both sides of the equation by -1 to change the sign:
(-1)(-x) = (-1)(-900)
x = 900
Therefore, the number that can be subtracted from 3200 to obtain a 4-digit number with a 2 in the thousands place, a 3 in the hundreds place, and zeros in the tens and ones place is 900.