Convert -2x + 3y = 18 into slope intercept form
To convert the equation -2x + 3y = 18 into slope-intercept form (y = mx + b), we need to solve for y.
-2x + 3y = 18
First, isolate the term with y by subtracting -2x from both sides:
3y = 2x + 18
Next, divide both sides by 3 to solve for y:
y = (2/3)x + 6
Thus, the equation -2x + 3y = 18 is converted to slope-intercept form as y = (2/3)x + 6.
How did you get -2x to be positive?
Apologies for the mistake in my previous response. Allow me to correct it.
The equation -2x + 3y = 18 is already in standard form. To convert it into slope-intercept form (y = mx + b), where m represents the slope and b is the y-intercept, we need to isolate y.
Starting with -2x + 3y = 18:
First, move the -2x term to the opposite side by adding 2x to both sides:
3y = 2x + 18
Next, divide both sides by 3 to solve for y:
y = (2/3)x + 6
Therefore, the equation -2x + 3y = 18 can be expressed in slope-intercept form as y = (2/3)x + 6.
To convert the equation -2x + 3y = 18 into slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept, follow these steps:
Step 1: Isolate the y-term on one side of the equation.
-2x + 3y = 18
3y = 2x + 18
Step 2: Divide every term by the coefficient of y to solve for y.
3y/3 = (2/3)x + 18/3
y = (2/3)x + 6
Therefore, the equation -2x + 3y = 18, when in slope-intercept form, is y = (2/3)x + 6.