Find the frequency and the period for each of following:
a) A light bulb turns on and off 60 times in 1s.
b) A bird flaps its wings 120 times in 6s.
a) The frequency of the light bulb turning on and off is 60 times per second. The period can be calculated by taking the reciprocal of the frequency, so the period is 1 second divided by 60, which is equal to 0.0167 seconds.
b) The frequency of the bird flapping its wings is 120 times in 6 seconds. To find the frequency, we divide the number of times the bird flaps its wings in 6 seconds by 6, which gives us a frequency of 20 times per second. The period can be calculated by taking the reciprocal of the frequency, so the period is 1 second divided by 20, which is equal to 0.05 seconds.
To find the frequency and period, we can use the following formulas:
Frequency (f) = 1 / Period (T)
Period (T) = 1 / Frequency (f)
Let's calculate the frequency and period for each scenario:
a) A light bulb turns on and off 60 times in 1 second.
Frequency (f) = 60 / 1 = 60 Hz
Period (T) = 1 / 60 = 0.0167 seconds
Therefore, the frequency is 60 Hz, and the period is approximately 0.0167 seconds.
b) A bird flaps its wings 120 times in 6 seconds.
Frequency (f) = 120 / 6 = 20 Hz
Period (T) = 1 / 20 = 0.05 seconds
Therefore, the frequency is 20 Hz, and the period is 0.05 seconds.