Imagine a scenario in which an animal's force is pushing itself forward 5 N, friction is pushing it 4 N backward, gravity is pushing the animal 10 N down, and the animal is pushing itself 10 N up. Describe the movement of the animal.(1 point)
Responses
In this scenario, the animal's force pushing itself forward is greater than the friction pushing it backward (5 N vs 4 N), so there is a net force of 1 N forward. However, the force of gravity pushing the animal down (10 N) is greater than its own upward force (10 N), resulting in a net force of 0 N downward.
As a result, the animal would experience a slight forward movement due to the net force of 1 N forward. However, because the net force in the vertical direction is 0 N, the animal would not experience any upward or downward movement.
Therefore, the movement of the animal would be primarily forward, with no significant change in vertical position.
The animal's force of 5 N pushing itself forward is opposed by the friction force of 4 N pushing it backward. Due to the imbalance of forces, the animal will experience a net force of 1 N pushing it in the forward direction. However, this forward movement is also opposed by the force of gravity pushing the animal down with a force of 10 N.
Since the force of gravity is greater than the net force of 1 N pushing the animal forward, the animal will not be able to overcome the force of gravity and move upward. Instead, it will experience a downward movement due to gravity.
In summary, the animal will move in a downward direction due to the force of gravity overpowering the net force acting in the forward direction.