A 12 ft by 15 ft rectangular swimming pool has a 4 ft wide no slip surface around it. What is the outer perimeter of the no-slip surface?
a70ft^2
b70ft
c86ft^2
d86ft
The length of the pool with the no-slip surface is 12 + 4 + 4 = <<12+4+4=20>>20 ft.
The width of the pool with the no-slip surface is 15 + 4 + 4 = <<15+4+4=23>>23 ft.
The outer perimeter of the no-slip surface is 2 * (20 + 23) = <<2*(20+23)=86>>86 ft.
The answer is d) 86 ft.
To find the outer perimeter of the no-slip surface, we need to add the dimensions of the pool and the width of the no-slip surface.
Given:
Length of the pool = 12 ft
Width of the pool = 15 ft
Width of the no-slip surface = 4 ft
To find the outer perimeter, we need to add the dimensions of the pool and two times the width of the no-slip surface, since it goes around the entire pool.
Outer perimeter = (Length of the pool + 2 * Width of the no-slip surface) + (Width of the pool + 2 * Width of the no-slip surface)
Let's calculate it:
Outer perimeter = (12 ft + 2 * 4 ft) + (15 ft + 2 * 4 ft)
Outer perimeter = (12 ft + 8 ft) + (15 ft + 8 ft)
Outer perimeter = 20 ft + 23 ft
Outer perimeter = 43 ft
So, the outer perimeter of the no-slip surface is 43 ft.
Therefore, the correct answer is d) 86 ft.