How many significant digits are in
7.0*10 to power of-3 mL
0.005900J
89300kg
-1.0*10 to power of-3 kJmol
The number 7.0 × 10^-3 mL has 2 significant digits.
The number 0.005900 J has 4 significant digits.
The number 89300 kg has 3 significant digits.
The number -1.0 × 10^-3 kJ/mol has 2 significant digits.
To determine the number of significant digits in a given number, follow these steps:
1. For numbers written in scientific notation (a × 10^b), count all the digits in the coefficient (a) except for leading and trailing zeros, and add it to the exponent (b). This will give you the number of significant digits.
Now let's calculate the significant digits for each given number:
1. 7.0 × 10^-3 mL:
- The coefficient is 7.0, with one leading zero.
- There are two significant digits in the coefficient.
- Adding the exponent (-3) gives us a total of two significant digits.
2. 0.005900 J:
- The coefficient is 0.005900.
- There is one leading zero, but trailing zeros after the decimal point count as significant.
- Therefore, there are four significant digits.
3. 89300 kg:
- The coefficient is 89300, with no leading or trailing zeros.
- There are five significant digits.
4. -1.0 × 10^-3 kJ/mol:
- The coefficient is -1.0, with one leading zero.
- There are two significant digits in the coefficient.
- Adding the exponent (-3) gives us a total of two significant digits.
Therefore, the number of significant digits for each given number is as follows:
- 7.0 × 10^-3 mL: 2 significant digits
- 0.005900 J: 4 significant digits
- 89300 kg: 5 significant digits
- -1.0 × 10^-3 kJ/mol: 2 significant digits