11base x +10base y=10001base 2
10base x - y=10base 2
Plz solve and leave your ans in base 2
what garbage!
11base x +10base y=10001base 2
10base x - y=10base 2
--------------------------------
x+1 + y = 10001
x - y = 10
adding, we get
2x = 10011
I suspect a typo, since we're getting into fractions here.
Also, the question is worded very strangely.
Apologies for any confusion caused. Let's solve the revised system of equations:
x + y + 1 = 10001base 2
x - y = 10base 2
Subtracting the second equation from the first, we eliminate x:
(x + y + 1) - (x - y) = 10001base 2 - 10base 2
x - x + y + y + 1 - (-y) = 10001base 2 - 10base 2
2y + 1 + y = 10001base 2 - 10base 2
3y + 1 = 10001base 2 - 10base 2
To proceed further, we need to know the base of y. Could you please clarify the base for y?
To solve the given system of equations and express the answers in base 2, we can use the substitution method:
1) Start by converting the given numbers to base 10:
11base x = 1*base x^1 + 1*base x^0 = x + 1 (in base 10)
10base y = 1*base y^1 + 0*base y^0 = y (in base 10)
10001base 2 = 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 1*2^0 = 17 (in base 10)
10base 2 = 1*2^1 + 0*2^0 = 2 (in base 10)
2) Rewrite the equations in base 10:
x + 1 + y = 17
x - y = 2
3) Solve the second equation for x: x = 2 + y
4) Substitute the value of x into the first equation:
(2 + y) + 1 + y = 17
2y + 3 = 17
2y = 14
y = 7
5) Substitute the value of y into x = 2 + y:
x = 2 + 7
x = 9
6) Convert the values of x and y to base 2:
x = 1001base 2
y = 111base 2
Therefore, the solution to the system of equations in base 2 is x = 1001base 2 and y = 111base 2.
To solve the given equations, we can convert the numbers to base 10, perform the arithmetic operations, and then convert the result back to base 2.
First, let's convert the given numbers to base 10:
11base x = 1*10^1 + 1*10^0 = 11
10base y = 1*10^1 + 0*10^0 = 10
10001base 2 = 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 1*2^0 = 17
10base x = 1*10^1 + 0*10^0 = 10
10base 2 = 1*2^1 + 0*2^0 = 2
Now, let's solve the equations in base 10:
11 - 10 = 1
10 - y = 2
y = 10 - 2 = 8
Next, let's convert the result back to base 2:
1base 10 = 1*2^0 = 1
8base 10 = 1*2^3 + 0*2^2 + 0*2^1 + 0*2^0 = 1000base 2
Therefore, the solution to the given system of equations in base 2 is:
x = 1base 2
y = 1000base 2