aye bruh
1. A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the rate of change in the squirrel’s height above the ground is -10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is -10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is -19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is -19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
The correct answer is:
The quotient that describes the rate of change in the squirrel’s height above the ground is -19.05 feet/second.
explai
To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it takes for the squirrel to move from the perch to the stored acorns.
In this case, the squirrel moves from a perch 100 feet above the ground to a hole 45 feet from the ground. The change in height is 100 - 45 = 55 feet.
The squirrel takes 5.25 seconds to make this movement.
To find the rate of change, we divide the change in height by the time:
Rate of change = 55 feet / 5.25 seconds
Calculating this value gives us approximately -10.48 feet/second.
However, we need the rate of change with the correct sign. Since the squirrel is moving downwards, the negative sign indicates that the squirrel is descending.
Therefore, the correct answer is:
The quotient that describes the rate of change in the squirrel’s height above the ground is -19.05 feet/second.
2. A dolphin jumped above the surface of the water. It reached an altitude of 3.5 meters above the surface of the water and then dove 10 meters below the surface of the water. It went from its highest point above the water to its lowest depth in 12.5 seconds. Interpret the quotient to describe the average rate of change in the dolphin’s position. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the rate of change in the dolphin’s position is -1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is -1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is -0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is -0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 0.52 meters/second.
The correct answer is:
The quotient that describes the rate of change in the dolphin’s position is -0.52 meters/second.
The scuba diver was at a depth below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth.
(1 point)
Responses
The quotient that scribes the average rate of change for the diver’s depth is -0.99 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is -0.99 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is -3.47 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is -3.47 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that scribes the average rate of change for the diver’s depth is -0.49 meters/second.
The correct answer is:
The quotient that describes the average rate of change for the diver's depth is -0.99 meters/second.
Solve using division of rational numbers. If a car’s value decreases by $4,000 in the first 12 months, how much does the value decrease per month? (Round to the nearest hundredth.)(1 point)
Responses
−0.003
negative 0.003
0.003
0.003
−$333.33
negative 333.33 dollars
$333.33
To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took.
Given that the squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns 45 feet from the ground, the change in height would be 100 - 45 = 55 feet.
The time it took for the squirrel to move from the perch to the acorns is given as 5.25 seconds.
To find the rate of change, we divide the change in height (55 feet) by the time (5.25 seconds):
Rate of change = 55 feet / 5.25 seconds ≈ 10.48 feet/second.
Therefore, the correct answer is: The quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.