Calculate the mass of KH2PO4 (136.09 g/mole) you will need to prepare 550 mL of the 0.05 M solution.
To calculate the mass of KH2PO4 needed to prepare 550 mL of a 0.05 M solution, we can use the formula:
mass = molarity × volume × molar mass
First, let's calculate the moles of KH2PO4 needed:
moles = molarity × volume
= 0.05 mol/L × 0.55 L
= 0.0275 mol
Now, let's calculate the mass:
mass = moles × molar mass
= 0.0275 mol × 136.09 g/mol
= 3.716 g
Therefore, you will need 3.716 grams of KH2PO4 to prepare a 550 mL 0.05 M solution.
To calculate the mass of KH2PO4 needed to prepare a 0.05 M solution, you can use the formula:
Mass (g) = Molarity (M) x Volume (L) x Molecular Weight (g/mol)
First, let's convert the volume from milliliters (mL) to liters (L):
550 mL = 550/1000 L = 0.55 L
Next, substitute the given values into the formula:
Mass (g) = 0.05 M x 0.55 L x 136.09 g/mol
Mass (g) = 3.68 g
Therefore, you will need 3.68 grams of KH2PO4 to prepare 550 mL of a 0.05 M solution.