FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Element Mass of an Atom (amu)
Fe 56
Cl 35
H 1
O 16
Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
215 amu
108amu
161 amu
179 amu
To find the total mass of the reactants, we need to calculate the mass of each individual reactant and then add them together.
For FeCl3, we have 1 atom of Fe (56 amu) and 3 atoms of Cl (35 amu each), so the mass of FeCl3 is 56 amu + (3 x 35 amu) = 56 amu + 105 amu = 161 amu.
For H2O, we have 2 atoms of H (1 amu each) and 1 atom of O (16 amu), so the mass of H2O is (2 x 1 amu) + 16 amu = 2 amu + 16 amu = 18 amu.
Therefore, the total mass of the reactants is 161 amu + 18 amu = 179 amu.
So the correct answer is 179 amu.
To find the total mass of the reactants, we need to sum the individual masses of all the atoms present in the reactants.
Given:
FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Let's calculate the total mass of FeCl3:
FeCl3 = Fe + 3(Cl)
FeCl3 = 56 + 3(35) = 56 + 105 = 161 amu
Now let's calculate the total mass of H2O:
H2O = 2(H) + 1(O)
H2O = 2(1) + 1(16) = 2 + 16 = 18 amu
Next, let's calculate the total mass of both FeCl3 and H2O:
Total mass of reactants = Total mass of FeCl3 + Total mass of H2O
Total mass of reactants = 161 amu + 3(18 amu)
Total mass of reactants = 161 amu + 54 amu
Total mass of reactants = 215 amu
Therefore, the total mass of the reactants is 215 amu.