in the experiment where collecting h2 gas form magnesium and sulfurci acid in 30 seconds what are two rate of reaction are they
eample gas produced / time
The two rates of reaction in the experiment can be:
1. The rate of consumption of magnesium: This can be calculated by measuring the mass of the magnesium before the reaction and after 30 seconds, and dividing the change in mass by the time elapsed. This will give the rate at which the magnesium is being consumed.
2. The rate of h2 gas produced: This can be calculated by measuring the volume of h2 gas collected after 30 seconds and dividing it by the time elapsed. This will give the rate at which the gas is being produced.
To calculate the rate of reaction in the experiment where hydrogen gas is produced from the reaction between magnesium and sulfuric acid, you can use the equation:
Rate of reaction = Amount of gas produced / Time
Given that the experiment collects the hydrogen gas over a period of 30 seconds, let's assume that 50 mL of hydrogen gas is collected in that time frame. The rate of reaction can then be calculated as follows:
Rate of reaction = 50 mL / 30 seconds
Simplifying the equation:
Rate of reaction = 5/3 mL/s
So, the rate of reaction in this experiment is 5/3 mL/s.