A rigid volume contains 6 m3 of steam originally at a pressure and temperature that gives U1 as 1.324 kJ/kg and U2 as 1.978 m/kg on the steam tables. Estimate the final temperature if 800 J of heat is added.

To estimate the final temperature, we need to calculate the specific volume (v1) and specific internal energy (u1) of the steam initially in the volume.

Given:
- Volume (V) = 6 m^3
- Internal energy (u1) = 1.324 kJ/kg = 1324 J/kg
- Internal energy (u2) = 1.978 kJ/kg = 1978 J/kg
- Heat added (Q) = 800 J

First, let's calculate the mass (m) of steam in the volume using the specific volume formula: V = m/v1

m = V/v1

To calculate v1, we can use the specific internal energy formula: u1 = h1 - P1*v1, where h1 is the specific enthalpy and P1 is the initial pressure.

Since we are not given the specific enthalpy, we cannot directly solve for v1. However, we can make an estimation by assuming the steam in the volume is saturated. In this case, the enthalpy can be approximated as the specific internal energy plus the product of the specific volume and saturation pressure: h1 ≈ u1 + P_sat*v1.

Let's assume that the saturated temperature (T1) at the given internal energy u1 is close to the initial temperature of the steam. Using the steam tables, we can find the saturation pressure (P_sat) at T1.

Next, we can use the estimated h1 to solve for v1: u1 = h1 - P_sat*v1.

Once we have v1, we can calculate the mass m: m = V/v1.

Finally, we can calculate the final temperature using the equation: Q = m*(u2 - u1) + m*C_v*(T2 - T1), where C_v is the specific heat capacity at constant volume.

In this case, we are not given the initial and final pressures, so we'll assume constant volume and use the specific heat capacity at constant volume as an approximation for C_v.

Let's follow these steps to estimate the final temperature:

1. Find the saturation pressure (P_sat) at the estimated initial temperature T1.
2. Calculate the estimated enthalpy (h1) using the equation h1 ≈ u1 + P_sat*v1.
3. Solve for v1 using the equation u1 = h1 - P_sat*v1.
4. Calculate the mass (m) of steam using the equation m = V/v1.
5. Plug in the values of m, u1, u2, C_v, and Q into the equation Q = m*(u2 - u1) + m*C_v*(T2 - T1).
6. Rearrange the equation for T2 to solve for the final temperature.

Note: The calculations will involve interpolation from the steam tables.

To estimate the final temperature, we can use the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

The equation can be written as:

ΔU = Q - W

In this case, we have a rigid volume, which means no work is done (W = 0). Therefore, the equation simplifies to:

ΔU = Q

Given that ΔU = U2 - U1, and Q = 800 J, we can substitute these values into the equation:

U2 - U1 = Q

1.978 - 1.324 = 800

0.654 = 800

To find the final temperature, we need to use the Specific Heat formula:

Q = m * C * ΔT

Where:
Q = Heat added
m = Mass
C = Specific heat capacity
ΔT = Change in temperature

Since we are given the heat added (Q = 800 J) and the change in internal energy (ΔU = U2 - U1 = 0.654 kJ/kg = 654 J/kg), we can solve for the mass (m) using the equation:

800 = m * C * 654

Dividing both sides of the equation by (m * C):

800 / (m * C) = 654

Now, we substitute the given values for U1 and U2 into the equation to find the average specific heat capacity (C):

C = (U2 - U1) / 1000

C = (1.978 - 1.324) / 1000

C = 0.654 / 1000

C = 0.000654 kJ/kg

Substituting the value of C back into the equation:

800 / (m * 0.000654) = 654

Dividing both sides of the equation by 0.000654:

m = 800 / (654 * 0.000654)

m ≈ 1938 kg

Now we can find the change in temperature using the equation:

ΔT = Q / (m * C)

ΔT = 800 / (1938 * 0.000654)

ΔT ≈ 0.627 °C

Finally, to estimate the final temperature, we add this change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

Assuming the initial temperature is T1:

Final temperature ≈ T1 + 0.627 °C

Please note that without the initial temperature (T1), we cannot provide an exact value for the final temperature.