A bird is flying at an average altitude of 10 meters above ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird's altitude. Give your answer to the nearest hundredth and remember that the bird is descending.
It's -2.33 btw
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the whale’s depth is
meters/second.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point) The quotient that best represents the rate of change in the bird’s altitude is meters/second.
To interpret the quotient that describes the rate of change in the bird's altitude, we can use the formula for average velocity:
Velocity = Change in altitude / Change in time
In this case, the change in altitude is 10 meters (starting altitude of 10 meters above the ground minus the altitude of 3 meters on the branch) and the change in time is 3 seconds.
Plugging these values into the formula:
Velocity = 10 meters / 3 seconds
Calculating this:
Velocity ≈ 3.333 meters/second
Therefore, the rate of change in the bird's altitude is approximately 3.33 meters per second.
To interpret the quotient describing the rate of change in the bird's altitude, we need to divide the change in altitude by the change in time.
In this case, the change in altitude is the difference between the initial altitude (10 meters) and the final altitude (3 meters), which is 10 meters - 3 meters = 7 meters.
The change in time is given as 3 seconds.
So, to find the rate of change in the bird's altitude, we divide the change in altitude by the change in time: 7 meters / 3 seconds.
By performing this calculation, we find that the rate of change in the bird's altitude is approximately 2.33 meters per second (rounded to the nearest hundredth).
Therefore, the quotient 2.33 describes the rate of change in the bird's altitude as it descends to settle on the branch.
The change in altitude of the bird can be calculated by subtracting the final altitude from the initial altitude:
10 meters above ground - 3 meters above ground = 7 meters
Since the bird settles on the branch after 3 seconds, the rate of change in altitude can be calculated by dividing the change in altitude by the time taken:
7 meters / 3 seconds ≈ 2.33 meters per second.
Therefore, the quotient 2.33 describes the rate of change in the bird's altitude.