The sum of the ages of two brothers Kofi and Kweku is 35. If Kofi's age is 2 thirds kwaku's age. Find their ages
Let's assume Kofi's age is x and Kwaku's age is y.
Given that the sum of their ages is 35, we can write the equation:
x + y = 35 ...........(1)
Also given that Kofi's age is 2/3 Kwaku's age, we can write the equation:
x = (2/3)y ..........(2)
To solve these equations, we can substitute equation (2) into equation (1):
(2/3)y + y = 35
(5/3)y = 35
Multiply both sides by 3/5 to isolate y:
y = (35 * 3) / 5
y = 21
Substituting this value back into equation (2), we can solve for x:
x = (2/3)(21)
x = 14
Therefore, Kofi's age (x) is 14 and Kwaku's age (y) is 21.
Let's represent Kofi's age as "x" and Kwaku's age as "y".
According to the given information, the sum of Kofi and Kwaku's ages is 35:
x + y = 35 ------ Equation 1
It is also given that Kofi's age is two-thirds of Kwaku's age:
x = (2/3)y ------ Equation 2
To find their ages, we can solve these two equations simultaneously.
First, we will substitute Equation 2 into Equation 1:
(2/3)y + y = 35
Multiplying both sides of the equation by 3 to eliminate the fraction:
2y + 3y = 105
Combining like terms:
5y = 105
Dividing both sides by 5:
y = 21
Now that we have the value of y, we can substitute it back into Equation 2 to find x:
x = (2/3)(21) = 14
So, Kofi's age is 14 and Kwaku's age is 21.