A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
Responses
780
Start Fraction 7 over 80 End Fraction
776
Start Fraction 7 over 76 End Fraction
21190
Start Fraction 21 over 190 End Fraction
35
Start Fraction 7 over 20 End Fraction
To calculate the probability of selecting an apple and a banana from the basket, we need to find the total number of possible outcomes and the number of favorable outcomes.
Total number of possible outcomes:
There are a total of 20 fruits in the basket. When we select two fruits without replacement, the first fruit can be any of the 20 fruits, and the second fruit can be any of the remaining 19 fruits. Therefore, the total number of possible outcomes is 20 * 19 = 380.
Number of favorable outcomes:
There are 7 apples and 5 bananas in the basket. Since we need to select one apple and one banana, the number of ways to select an apple is 7, and the number of ways to select a banana is 5. Therefore, the number of favorable outcomes is 7 * 5 = 35.
Probability:
The probability of selecting an apple and a banana is given by the number of favorable outcomes divided by the total number of possible outcomes.
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 35 / 380
Probability = 7/76
So, the probability of selecting an apple and a banana is Start Fraction 7 over 76 End Fraction.