MATH 7A
Add And Subtract Rational Numbers Unit Test.
Solve the following word problem. The air temperature at 9 a.m. is -5.8 degrees Celsius. The air temperature at noon is -1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means. (4 points)
To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.
Let's represent the initial temperature as -5.8 degrees Celsius and the final temperature as -1.6 degrees Celsius.
The equation to find the change in temperature is:
Change in temperature = Final temperature - Initial temperature
Change in temperature = -1.6 - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2
Therefore, the change in temperature during these three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.
To find the change in temperature during the three hours, we can subtract the temperature at 9 a.m. from the temperature at noon.
Let's denote the temperature at 9 a.m. as T1, and the temperature at noon as T2.
Given:
T1 = -5.8 degrees Celsius
T2 = -1.6 degrees Celsius
The change in temperature, denoted as ΔT, can be calculated using the equation:
ΔT = T2 - T1
Substituting the given values:
ΔT = (-1.6) - (-5.8)
To subtract a negative number, we can change the sign and add the numbers:
ΔT = -1.6 + 5.8
Now, let's perform the addition:
ΔT = 4.2
Therefore, the change in temperature during the three hours is 4.2 degrees Celsius.
This positive value indicates that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.