bot. What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.(1 point)
To find the sum of the absolute deviations, we need to subtract the mean from each data point, take the absolute value of each difference and then sum them up.
The differences from the mean for each data point are:
63 - 47.9 = 15.1
25 - 47.9 = -22.9
74 - 47.9 = 26.1
52 - 47.9 = 4.1
63 - 47.9 = 15.1
12 - 47.9 = -35.9
46 - 47.9 = -1.9
Taking the absolute values, we have:
|15.1| = 15.1
|(-22.9)| = 22.9
|26.1| = 26.1
|4.1| = 4.1
|15.1| = 15.1
|(-35.9)| = 35.9
|(-1.9)| = 1.9
Summing up these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120.1
Therefore, the sum of the absolute deviations in the dataset is 120.1 (rounded to the nearest tenth).
wrong answer
I apologize for the incorrect answer.
To find the sum of the absolute deviations, we need to subtract the mean from each data point, take the absolute value of each difference, and then sum them up.
The differences from the mean for each data point are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing up these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120.1
Therefore, the correct sum of the absolute deviations in the dataset is 120.1, rounded to the nearest tenth.
its still wrong
I apologize for the mistake again. Let me recalculate it correctly this time.
To find the sum of the absolute deviations, we need to subtract the mean from each data point, take the absolute value of each difference, and then sum them up.
The differences from the mean for each data point are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing up these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120
Therefore, the sum of the absolute deviations in the dataset is 120.
not it
Apologies for the previous incorrect responses. Let's calculate the correct sum of the absolute deviations.
To find the sum of the absolute deviations, we need to subtract the mean from each data point, take the absolute value of each difference, and then sum them up.
The differences from the mean for each data point are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing up these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120.1
Therefore, the sum of the absolute deviations in the dataset is 120.1 (rounded to the nearest tenth).
120.1 isnt correct
I apologize for the repeated errors. Let's calculate the correct sum of the absolute deviations.
To find the sum of the absolute deviations, we need to subtract the mean from each data point, take the absolute value of each difference, and then sum them up.
The differences from the mean for each data point are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing up these absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120.1
I apologize again for the error in my previous response. The correct sum of the absolute deviations in the dataset is indeed 120.1.
Here are the high temperatures (in Fahrenheit) for a 10-day period in Salinas, California, in December:
58, 59, 61, 62, 62, 62, 63, 64, 66, 67
Find the range and explain what the value means for this dataset.
(2 points)
The range is
degrees Fahrenheit; this is the difference in degrees Fahrenheit between
degrees, the minimum temperature, and
degrees, the maximum temperature.