Match the equation with its solution.(5 points)

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3i+2i−7=18
3(2i−7)=15
3i+5=2i−7
3i+5=3i+7
3(2i+7)=6i+21

Equation: 3i+2i−7=18

Solution: i = 5

Equation: 3(2i−7)=15
Solution: i = 6

Equation: 3i+5=2i−7
Solution: No solution

Equation: 3i+5=3i+7
Solution: No solution

Equation: 3(2i+7)=6i+21
Solution: All real numbers

Ur last two answers are wrong bot

Let's go through each equation and match it with its solution:

1. Equation: 3i+2i−7=18
Solution: 3(2i−7)=15

2. Equation: 3i+5=2i−7
Solution: No solution

3. Equation: 3i+5=3i+7
Solution: No solution

4. Equation: 3(2i+7)=6i+21
Solution: True for all values of i

Therefore, the correct matches are:

1. 3i+2i−7=18 --> Solution: 3(2i−7)=15
2. 3i+5=2i−7 --> Solution: No solution
3. 3i+5=3i+7 --> Solution: No solution
4. 3(2i+7)=6i+21 --> Solution: True for all values of i

To match each equation with its solution, we can solve each equation one by one to find the corresponding solution. Let's go through each equation:

1. 3i + 2i - 7 = 18

To solve this equation, we group the like terms:
(3i + 2i) - 7 = 18
5i - 7 = 18

Next, we isolate the variable:
5i = 18 + 7
5i = 25

Finally, we solve for i by dividing both sides by 5:
i = 25/5
i = 5

So, the solution for equation 1 is i = 5.

2. 3(2i - 7) = 15

To solve this equation, we distribute 3 to the terms inside the parentheses:
6i - 21 = 15

Next, we isolate the variable:
6i = 15 + 21
6i = 36

Finally, we solve for i by dividing both sides by 6:
i = 36/6
i = 6

So, the solution for equation 2 is i = 6.

3. 3i + 5 = 2i - 7

To solve this equation, we isolate the variable by subtracting 2i from both sides:
3i - 2i + 5 = -7

Simplifying, we get:
i + 5 = -7

Next, we isolate the variable by subtracting 5 from both sides:
i = -7 - 5
i = -12

So, the solution for equation 3 is i = -12.

4. 3i + 5 = 3i + 7

To solve this equation, we subtract 3i from both sides:
3i - 3i + 5 = 3i - 3i + 7
5 = 7

This is a contradiction because 5 does not equal 7. Therefore, this equation has no solution.

So, the solution for equation 4 is "No solution".

5. 3(2i + 7) = 6i + 21

To solve this equation, we distribute 3 to the terms inside the parentheses:
6i + 21 = 6i + 21

This equation is an identity because both sides are equal, regardless of the value of i. Therefore, this equation has infinitely many solutions.

So, the solution for equation 5 is "Infinitely many solutions".

To summarize the matches:
Equation 1: Solution is i = 5
Equation 2: Solution is i = 6
Equation 3: Solution is i = -12
Equation 4: No solution
Equation 5: Infinitely many solutions