2/5 of a number of pupils in a class is 4 greater than three-quarter of the number in the class. Find the number of pupils in the class
Let's say the number of pupils in the class is x.
According to the information given, 2/5 of x is 4 greater than 3/4 of x.
This can be written as (2/5)x = (3/4)x + 4.
To eliminate the fractions, we can multiply both sides of the equation by 20 (the least common denominator).
20 * (2/5)x = 20 * ((3/4)x + 4).
Simplifying, we get:
8x = 15x + 80.
Subtracting 15x from both sides, we get:
8x - 15x = 80.
-7x = 80.
Dividing both sides by -7, we have:
x = -80/7.
The number of pupils in the class is -80/7, which is approximately -11.43. However, since the number of pupils cannot be negative or fractional, we can conclude that there was an error in the original equation or information given. Please double-check the information and revise the question if necessary.
Let's assume the number of pupils in the class is "x".
According to the given information, 2/5 of the number of pupils in the class is 4 greater than three-quarters of the number.
This can be written as:
2/5 * x = 3/4 * x + 4
To simplify the equation, let's multiply each term by 20 (the least common multiple of 5 and 4):
20 * (2/5 * x) = 20 * (3/4 * x) + 20 * 4
8x = 15x + 80
Next, we'll move the terms with x to one side of the equation:
8x - 15x = 80
-7x = 80
To isolate x, we divide both sides of the equation by -7:
x = 80 / -7
x ≈ -11.429
However, we cannot have a negative number of pupils in a class. Therefore, there seems to be an error in the given information or problem setup. Please double-check the question or provide more details if possible.