A man gave 4cedis 50 pesetas to his children ,Abraham,Sylvia and fred Abraham received twice as much as Sylvia and Sylvia received thrice as much as Fred.Find how much Abraham received
Let's assume that Fred received x cedis 50 pesetas.
So, Sylvia received 3x cedis 50 pesetas.
And Abraham received 2 * (3x cedis 50 pesetas) = 6x cedis 50 pesetas.
Given that the total amount of money given was 4 cedis 50 pesetas,
x + 3x + 6x = 4.5
10x = 4.5
x = 4.5 / 10
x = 0.45 cedis 50 pesetas
Therefore, Abraham received 6 * 0.45 cedis 50 pesetas = 2.7 cedis 50 pesetas. Answer: \boxed{2.7}.
Let's assume that Fred received x cedis.
Since Sylvia received thrice as much as Fred, she received 3x cedis.
And Abraham received twice as much as Sylvia, so he received 2 * 3x = 6x cedis.
We know that the total amount given to the children is 4 cedis and 50 pesetas, which is equal to 4.50 cedis.
So, we can write the equation as:
x + 3x + 6x = 4.50
Combining like terms:
10x = 4.50
Dividing both sides by 10:
x = 0.45 cedis
Therefore, Abraham received 6x = 6 * 0.45 = 2.70 cedis.