An and shen opened a savings account and opened her account with the starting amount of 160 and she plans to put $50 in per month sheen opens his account with no starting money and he's going to put $90 in per month write an equation to show when the two accounts have the same amount of money
Let's assume that the number of months since the accounts were opened is represented by the variable "t".
For An's savings account, the equation can be written as:
Amount in An's account = Starting amount + (Amount deposited per month * Number of months)
Amount in An's account = 160 + (50 * t)
For Shen's savings account, the equation can be written as:
Amount in Shen's account = Starting amount + (Amount deposited per month * Number of months)
Amount in Shen's account = 0 + (90 * t)
To find when the two accounts have the same amount of money, we can set these two equations equal to each other:
160 + (50 * t) = 0 + (90 * t)
Simplifying the equation will give the solution.
Let's assume the number of months since they opened their accounts is represented by "m".
For An's account, the amount of money after m months can be expressed as:
A(m) = 160 + 50m
For Shen's account, the amount of money after m months can be expressed as:
S(m) = 90m
To find when the two accounts have the same amount of money, we can set the equations equal to each other and solve for "m":
A(m) = S(m)
160 + 50m = 90m
Simplifying the equation:
160 = 90m - 50m
160 = 40m
Dividing both sides of the equation by 40:
160/40 = m
4 = m
Therefore, the two accounts will have the same amount of money after 4 months.