Toss two dice. Predict how many times in 120 tosses an even number will appear on both dice.
To predict how many times an even number will appear on both dice in 120 tosses, we first need to determine the probability of getting an even number on one toss.
There are 6 possible outcomes for each die roll: 1, 2, 3, 4, 5, or 6.
Out of these 6 outcomes, 3 are even numbers: 2, 4, and 6.
Therefore, the probability of getting an even number on one toss is 3/6 = 1/2.
Now, we can calculate the expected number of times an even number will appear on both dice in 120 tosses by multiplying the probability of one event occurring by the total number of tosses.
Expected number of times = (probability of one toss) x (total number of tosses)
Expected number of times = (1/2) x 120
Expected number of times = 60
Therefore, we can predict that an even number will appear on both dice approximately 60 times in 120 tosses.
To predict how many times an even number will appear on both dice in 120 tosses, we first need to determine the probability of rolling an even number on one die.
An ordinary six-sided die has 3 even numbers (2, 4, and 6) and 3 odd numbers (1, 3, and 5). Thus, the probability of rolling an even number on one die is 3/6, or 1/2.
Since rolling a die is an independent event, the probability of rolling an even number with both dice is the product of their individual probabilities.
Therefore, the probability of rolling an even number on both dice is (1/2) * (1/2) = 1/4.
To find the number of times an even number will appear on both dice in 120 tosses, we multiply the total number of tosses by the probability of the event:
120 * (1/4) = 30
Hence, in 120 tosses, it is predicted that an even number will appear on both dice around 30 times.