Joey walked east for 15 and 2/3 meters from home then he walked west for 21 and 3/4 meters. How far was Joey from home?
To find the total distance from home, we subtract the distance from the eastward walk from the westward walk: 21 and 3/4 - 15 and 2/3 = (21 + 3/4) - (15 + 2/3) = 21 + 3/4 - 15 - 2/3 = 21 - 15 + 3/4 - 2/3 = 6 + 3/4 - 2/3
To add the fractions 3/4 and 2/3, we find a common denominator of 12: (3/4) * (3/3) = 9/12 and (2/3) * (4/4) = 8/12
Now we have 6 + 9/12 - 8/12 =
6 + (9 - 8)/12 =
6 + 1/12
Finally, the total distance from home is 6 + 1/12 = <<6+1/12=6 1/12>>6 1/12 meters. Answer: \boxed{6 \frac{1}{12}}.
To find how far Joey is from home, we need to calculate the total distance he walked east and west.
First, let's convert the mixed numbers, 15 and 2/3 and 21 and 3/4, into improper fractions:
15 and 2/3 = (3 * 15 + 2)/3 = 47/3 meters
21 and 3/4 = (4 * 21 + 3)/4 = 87/4 meters
Now, we can find the total distance by adding the distances:
47/3 + 87/4
To add these fractions, we need to find a common denominator, which in this case is 12.
Converting the fractions to have a common denominator of 12:
(47/3) * (4/4) = 188/12
(87/4) * (3/3) = 261/12
Adding the fractions now:
188/12 + 261/12 = 449/12
So, Joey is a total of 449/12 meters away from home.
However, let's simplify the fraction:
449/12 = 37 and 5/12
Therefore, Joey is approximately 37 and 5/12 meters away from home.