Write the electron configuration for Sm (Z=62) and how many upaired electrons
The electron configuration for Sm (Z=62) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁰ 6p⁶
So, the electron configuration for Sm is [Xe] 4f¹⁴ 6s².
In the 4f sublevel, there are 14 electrons, which are all paired. In the 6s sublevel, there are 2 electrons, which are also paired. Therefore, there are no unpaired electrons in the electron configuration of Sm.
How many upaired electrons are in SM(Z=62).
Apologies for the mistake in my previous response. Let me correct it.
The electron configuration for Sm (Z=62) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁰ 6p⁶
To determine the number of unpaired electrons, we need to consider the electron configuration in the outermost energy level, which in this case is 6s² 4f¹⁴.
In a neutral atom of Sm, the 6s² sublevel is filled completely, meaning both electrons in the sublevel are paired.
The 4f sublevel can hold a total of 14 electrons. In Sm, all 14 of these electrons are present. However, there are two sublevels within the 4f sublevel, 4f₁⁴ and 4f¹³5d¹.
Since the 4f¹⁴ sublevel is full and has all electrons paired, there are no unpaired electrons in the 4f sublevel.
Therefore, Sm (Z=62) has a total of 0 unpaired electrons.
The electron configuration for Sm (samarium, Z=62) can be determined by following the Madelung's rule. I will provide the electron configuration both in the spdf notation and the orbital notation.
The electron configuration for Sm is: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^6 5d^0 6p^0.
In the spdf notation:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2
4d^10 5p^6 6s^2 4f^6 5d^0 6p^0.
In the orbital notation:
1s 2s 2p 3s 3p 4s 3d 4p 5s
4d 5p 6s 4f 5d 6p.
Now, to determine the number of unpaired electrons, we can look at the electron configuration of Sm. In this case, Sm has a partially filled 4f sublevel with 6 electrons. Therefore, there are 6 unpaired electrons in the outermost energy level.