A body moving with an initial velocity of 2 meter per second accelerates uniformly at 0.5 meter per second square. What is its velocity? 10 seconds after start.
v = v0 + at = 2 + 0.5 * 10 = 7 m/s
After 10 seconds, the velocity of the body would be 7 meters per second.
To find the velocity of the body after 10 seconds, we can use the formula for uniformly accelerated motion:
Velocity (v) = Initial Velocity (u) + (Acceleration (a) x Time (t))
Given:
Initial velocity (u) = 2 m/s
Acceleration (a) = 0.5 m/s^2
Time (t) = 10 s
Substituting the values into the formula:
Velocity (v) = 2 m/s + (0.5 m/s^2 x 10 s)
Calculating:
Velocity (v) = 2 m/s + (5 m/s)
Velocity (v) = 7 m/s
Therefore, the velocity of the body 10 seconds after start is 7 meters per second.
To find the velocity of the body 10 seconds after the start, we can use the equation of motion:
v = u + at
Where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Given:
Initial velocity (u) = 2 m/s
Acceleration (a) = 0.5 m/s^2
Time (t) = 10 seconds
Using the equation of motion, we can substitute the given values and solve for the final velocity:
v = u + at
v = 2 m/s + (0.5 m/s^2) * 10 s
v = 2 m/s + 5 m/s
v = 7 m/s
Therefore, the velocity of the body 10 seconds after the start is 7 meters per second.