X = 6y -3
2x + 7y = 13
To solve this system of equations, we can substitute the expression for X in terms of y from the first equation into the second equation:
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Now substitute y = 1 into the first equation to find the value of X:
X = 6(1) - 3
X = 3
Therefore, the solution to the system of equations is X = 3 and y = 1.
To solve the system of equations:
Equation 1: X = 6y - 3 (1)
Equation 2: 2x + 7y = 13 (2)
Step 1: We can start by substituting the value of X from equation (1) into equation (2).
In equation (2), instead of x, we can substitute (6y - 3) as follows:
2(6y - 3) + 7y = 13
Step 2: Simplify the equation by expanding and combining like terms:
12y - 6 + 7y = 13
19y - 6 = 13
Step 3: Move the constant term (6) to the other side of the equation:
19y = 13 + 6
19y = 19
Step 4: Divide both sides of the equation by the coefficient of y (19) to isolate y:
y = 19 / 19
y = 1
Step 5: Now we have the value of y (y = 1), and we can substitute it back into equation (1) to find the value of X:
X = 6(1) - 3
X = 6 - 3
X = 3
Step 6: The solution to the system of equations is X = 3 and y = 1.