The kinetic energy of a 25-gram bullet traveling at 500 m/s is:
Choose the best answer from the options below:
A 6.250 KJ
B 12.500 KJ
C 312.50 KJ
D 3.125 KJ
E 6.250 KJ
To calculate the kinetic energy (KE) of the bullet, we can use the formula: KE = (1/2)mv^2
Given:
m = 25 grams = 0.025 kg
v = 500 m/s
Plugging these values into the formula, we get:
KE = (1/2)(0.025 kg)(500 m/s)^2
= (1/2)(0.025 kg)(250000 m^2/s^2)
= 3125 J
So, the kinetic energy of the bullet is 3125 J.
Converting this to kilojoules (KJ), we divide by 1000:
3125 J รท 1000 = 3.125 KJ
Therefore, the correct answer is D) 3.125 KJ.
To find the kinetic energy of an object, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
First, convert the mass of the bullet from grams to kilograms:
25 grams = 25/1000 = 0.025 kilograms
Now, substitute the values into the formula:
Kinetic Energy = (1/2) * 0.025 kg * (500 m/s)^2
Solving this equation, you get:
Kinetic Energy = (1/2) * 0.025 kg * (250,000 m^2/s^2)
Kinetic Energy = 3,125 J
Therefore, the kinetic energy of the 25-gram bullet traveling at 500 m/s is 3.125 J.
The correct answer is option D: 3.125 KJ.