What is the new point when you rotate a geometric figure with point (5, 8) 270 degrees counterclockwise about the origin
alright i have the answers their all right
8, -5
-6, 4
-8, 5
6 -4
-5, 9
most likely (8, -5) for the first question
joshua is 5/5
To rotate a point (x, y) 270 degrees counterclockwise about the origin, we can use the following formulas:
x' = x * cos(theta) - y * sin(theta)
y' = x * sin(theta) + y * cos(theta)
In this case, we have a point (5, 8) and we want to rotate it 270 degrees counterclockwise.
Using the formulas, we substitute the values into the equations:
x' = 5 * cos(270°) - 8 * sin(270°)
y' = 5 * sin(270°) + 8 * cos(270°)
Since cos(270°) = 0 and sin(270°) = -1, the equations simplify to:
x' = 5 * 0 - 8 * (-1) = 8
y' = 5 * (-1) + 8 * 0 = -5
Therefore, the new point after rotating (5, 8) 270 degrees counterclockwise about the origin is (8, -5).
W person for telll us this is al right WOOOO !!! it REAL GUYS
tysm joshua ^^
To rotate a geometric figure counterclockwise 270 degrees about the origin, we can use the following formula:
For a point (x, y) rotated counterclockwise θ degrees about the origin, the new point (x', y') is given by:
x' = x * cos(θ) - y * sin(θ)
y' = x * sin(θ) + y * cos(θ)
In this case, the point given is (5, 8), and we want to rotate it 270 degrees counterclockwise. Let's substitute the values into the formulas:
θ = 270 degrees
x = 5
y = 8
Using the formulas, we get:
x' = 5 * cos(270°) - 8 * sin(270°)
y' = 5 * sin(270°) + 8 * cos(270°)
Now let's calculate cos(270°) and sin(270°):
cos(270°) = -1
sin(270°) = 0
Substituting the values and simplifying:
x' = 5 * (-1) - 8 * 0
= -5
y' = 5 * 0 + 8 * (-1)
= -8
Therefore, when you rotate the point (5, 8) 270 degrees counterclockwise about the origin, the new point is (-5, -8).