Given the equation: n2 202--> 2noz, what mass of oxygen is required to react completely with 71.909 g of nitrogen?
To determine the mass of oxygen required to react completely with nitrogen, we need to start by balancing the equation.
The balanced equation for the reaction is:
2N₂ + O₂ → 2N₂O
From the balanced equation, we can see that 2 moles of nitrogen react with 1 mole of oxygen to produce 2 moles of nitrogen oxide.
To calculate the mass of oxygen required, we'll use the molar masses of nitrogen (N₂) and oxygen (O₂) as well as the given mass of nitrogen (71.909 g).
The molar mass of nitrogen (N₂) is 28.02 g/mol.
The molar mass of oxygen (O₂) is 32.00 g/mol.
First, we need to calculate the number of moles of nitrogen:
moles of nitrogen = mass of nitrogen / molar mass of nitrogen
= 71.909 g / 28.02 g/mol
≈ 2.566 mol
Since 2 moles of nitrogen react with 1 mole of oxygen, we can calculate the moles of oxygen required:
moles of oxygen = (2/1) * moles of nitrogen
= 2.566 mol
≈ 5.132 mol
Finally, we can calculate the mass of oxygen required:
mass of oxygen = moles of oxygen * molar mass of oxygen
= 5.132 mol * 32.00 g/mol
≈ 164.224 g
Therefore, approximately 164.224 g of oxygen is required to react completely with 71.909 g of nitrogen.
To determine the mass of oxygen required to react completely with 71.909 g of nitrogen, we can use the balanced chemical equation n2 + 2o2 --> 2no.
The balanced equation shows that 1 mole of nitrogen (N2) reacts with 2 moles of oxygen (O2) to produce 2 moles of nitric oxide (NO).
Step 1: Convert the mass of nitrogen to moles using its molar mass.
Molar mass of nitrogen (N2) = 2 * atomic mass of nitrogen
= 2 * 14.007 g/mol
= 28.014 g/mol
Number of moles of nitrogen = mass of nitrogen / molar mass of nitrogen
= 71.909 g / 28.014 g/mol
= 2.568 mol
Step 2: Use the stoichiometric ratio between nitrogen and oxygen to determine the number of moles of oxygen required.
From the balanced equation, we see that 1 mole of nitrogen reacts with 2 moles of oxygen.
Therefore, the number of moles of oxygen = 2 * number of moles of nitrogen
= 2 * 2.568 mol
= 5.136 mol
Step 3: Convert the number of moles of oxygen to mass using its molar mass.
Molar mass of oxygen (O2) = 2 * atomic mass of oxygen
= 2 * 15.999 g/mol
= 31.998 g/mol
Mass of oxygen = number of moles of oxygen * molar mass of oxygen
= 5.136 mol * 31.998 g/mol
= 164.29 g
Therefore, the mass of oxygen required to react completely with 71.909 g of nitrogen is approximately 164.29 grams.