Determine the final volume of the solution if 0.783 grams of Na2CO3 is used to make a 0 348 M solution
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To determine the final volume of the solution, we need to use the formula:
molarity = moles of solute / volume of solution
First, we need to find the moles of Na2CO3:
moles = mass / molar mass
The molar mass of Na2CO3 is:
2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol
moles = 0.783 g / 105.99 g/mol = 0.00737 mol
Now we can rearrange the formula to solve for the volume of solution:
volume of solution = moles of solute / molarity
volume of solution = 0.00737 mol / 0.348 mol/L = 0.0212 L
So, the final volume of the solution is 0.0212 L or 21.2 mL.
To determine the final volume of the solution, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's calculate the moles of Na2CO3 using the given mass:
moles = mass / molar mass
The molar mass of Na2CO3 can be calculated by adding the atomic masses of each element:
Na: 22.99 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
Molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol
moles of Na2CO3 = 0.783 g / 105.99 g/mol = 0.00738 mol
Now, we can use the molarity equation to solve for the volume of the solution:
0.348 M = 0.00738 mol / volume
Rearranging the equation, we get:
volume = 0.00738 mol / 0.348 M
volume ≈ 0.0212 L or 21.2 mL
Therefore, the final volume of the solution is approximately 21.2 mL.