Calculate the mass of sulphur ric(six)acid in 250 cm3 of a solution whose concentration is 0.25 mole dm-3
To calculate the mass of sulfuric acid (H2SO4) in 250 cm3 of a solution with a concentration of 0.25 mole dm-3, we need to use the equation:
n = c x V
Where:
n = moles of solute
c = concentration in moles per dm3 (mol dm-3)
V = volume of solution in dm3
First, we need to convert the volume from cm3 to dm3:
250 cm3 ÷ 1000 = 0.25 dm3
Now we can calculate the moles of sulfuric acid:
n = 0.25 mol dm-3 x 0.25 dm3
n = 0.0625 moles
The relative molecular mass (Molar Mass) of sulfuric acid (H2SO4) is:
H = 1 g/mol
S = 32 g/mol
O = 16 g/mol (2x Oxygen atoms)
So the molar mass of H2SO4 is:
(2x1) + 32 + (4x16) = 98 g/mol
To find the mass, we multiply the moles by the molar mass:
Mass = Moles x Molar Mass
Mass = 0.0625 moles x 98 g/mol
Mass = 6.125 g
Therefore, the mass of sulfuric acid in 250 cm3 of a solution with a concentration of 0.25 mole dm-3 is 6.125 grams.
To calculate the mass of sulfuric acid, we can use the formula:
mass (g) = concentration (mol/dm^3) × volume (dm^3) × molar mass (g/mol)
First, let's convert the volume from cm^3 to dm^3:
Volume (dm^3) = 250 cm^3 ÷ 1000 cm^3/dm^3
Volume (dm^3) = 0.25 dm^3
The molar mass of sulfuric acid (H2SO4) can be calculated as:
Molar mass (H2SO4) = (2 × atomic mass of hydrogen) + atomic mass of sulfur + (4 × atomic mass of oxygen)
Molar mass (H2SO4) = (2 × 1.008 g/mol) + 32.06 g/mol + (4 × 16.00 g/mol)
Molar mass (H2SO4) = 98.09 g/mol
Now we can calculate the mass of sulfuric acid:
mass (g) = 0.25 mol/dm^3 × 0.25 dm^3 × 98.09 g/mol
mass (g) = 6.13 g
Therefore, the mass of sulfuric acid in 250 cm^3 of a solution with a concentration of 0.25 mol/dm^3 is 6.13 grams.