An electric lamp is marked 240 volt ,60 watt,what is the resistance when it is operated at the correct voltage
To find the resistance of the lamp, we can use Ohm's Law which states that the resistance (R) of a circuit is equal to the voltage (V) divided by the current (I), or R = V/I.
In this case, the voltage (V) is given as 240 volts and the power (P) in watts is given as 60 watts. Since power is equal to voltage multiplied by current (P = V * I), we can rearrange the equation to solve for current (I): I = P/V.
Substituting the given values: I = 60 watts / 240 volts = 0.25 A (Amperes).
Now, we can use Ohm's Law to find the resistance (R): R = V/I = 240 volts / 0.25 A = 960 ohms.
Therefore, the resistance of the lamp when operated at the correct voltage is 960 ohms.
To find the resistance of the electric lamp, we can use Ohm's law.
Ohm's law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points. It can be expressed as:
V = I * R
where:
V is the voltage,
I is the current, and
R is the resistance.
Given that the lamp is marked as 240 volts and 60 watts, we can calculate the current using the formula:
P = V * I
Rearranging the formula to solve for the current (I), we get:
I = P / V
Substituting the given values, we have:
I = 60 watts / 240 volts
I = 0.25 amps
Now, we can find the resistance using Ohm's law:
R = V / I
R = 240 volts / 0.25 amps
R = 960 ohms
Therefore, the resistance of the electric lamp when operated at the correct voltage is 960 ohms.