An electric lamp is marked 240watts,60watt.what is it's resistance when it is operated at the correct voltage
The question is incomplete as it does not provide the correct voltage at which the lamp is operated. Resistance can be calculated using Ohm's law, which states that resistance (R) is equal to voltage (V) divided by current (I). However, the current cannot be determined without knowing the voltage. Therefore, the answer cannot be calculated.
I expect there's a typo, and they meant "240volts, 60watt."
If so, then since P = E^2/R,
R = 240^2/60 = 960 Ω
Ah, that makes sense. In that case, you are correct. Using the formula P = E^2/R, we can rearrange the formula to get R = E^2/P, where E is the voltage and P is the power in watts. Thus, R = (240^2)/60 = 960 ohms. Therefore, the resistance of the lamp when it is operated at 240 volts and 60 watts is 960 ohms.
To find the resistance of the electric lamp, we need to use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I) flowing through the lamp.
Given:
Power rating of the lamp = 240 watts
Voltage of the correct operation = 60 volts
Step 1: Calculate the current (I) flowing through the lamp.
Using the formula: Power (P) = Voltage (V) × Current (I)
I = P / V = 240 watts / 60 volts = 4 amperes
Step 2: Calculate the resistance (R) using Ohm's Law.
R = V / I = 60 volts / 4 amperes = 15 ohms
Therefore, the resistance of the electric lamp when operated at the correct voltage is 15 ohms.
To find the resistance of the electric lamp, we can use Ohm's law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I).
First, let's determine the current. We have the power of the lamp, which is given as 240 watts and 60 watts.
For the 240-watt setting:
Using the formula: Power (P) = Voltage (V) x Current (I)
240 watts = V x I
However, we don't have the voltage, which is necessary to calculate the current.
For the 60-watt setting:
Using the same formula: Power (P) = Voltage (V) x Current (I)
60 watts = V x I
Now, let's determine the voltage.
Since the voltage is the same for both settings, we can equate the two expressions for power and solve for V.
240 watts = V x I
60 watts = V x I
We can divide the two equations to eliminate the current (I):
(240 watts / 60 watts) = (V x I) / (V x I)
4 = 1
This equation isn't valid: 4 does not equal 1. Hence, these conditions are not possible, and we can conclude that the lamp cannot operate at 240 watts and 60 watts simultaneously.
If you have additional information or if the given values are incorrect, please provide the correct details, and I'll be happy to help you further.