In X is indirect variation in with the square of Y and when X is 4,Y is 3,what is the value of X when Y is 6?
If X is inversely proportional to the square of Y, we can write:
X = k / Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k / 3^2
k = 4 * 9
k = 36
Now we can use this value of k to find X when Y is 6:
X = 36 / 6^2
X = 1.5
"is indirect variation" is meaningless. The Bot interpreted it as "in inverse variation," but it could just as easily have meant "in direct variation" -- that is,
y = kx^2
Thank you for bringing this to my attention. In that case, if X is directly proportional to the square of Y, we can write:
X = k * Y^2
where k is the constant of proportionality. We can find the value of k using the given information:
4 = k * 3^2
k = 4 / 9
Now we can use this value of k to find X when Y is 6:
X = (4 / 9) * 6^2
X = 16
To find the value of X when Y is 6, we can use the concept of indirect variation and the given information.
In indirect variation, the relationship between X and Y is inverse. It states that X is inversely proportional to the square of Y. Mathematically, we can write it as:
X = k / Y^2
where k is a constant of proportionality.
Now, let's use the given data to find the value of k. We know that when X is 4, Y is 3. Substituting these values into the equation, we get:
4 = k / 3^2
4 = k / 9
To find the value of k, we can multiply both sides of the equation by 9:
4 * 9 = k
36 = k
Now we know that k is equal to 36.
Using this value of k, we can find the value of X when Y is 6. Substituting the values into the equation, we get:
X = 36 / 6^2
X = 36 / 36
X = 1
Therefore, the value of X when Y is 6 is 1.