When a pulse is applied to an op-amp, the output voltage goes from -8 V to
+7 V in 0.75 us. What is the slew rate?
The slew rate is the maximum rate of change of the output voltage per unit of time.
To calculate the slew rate, we need to first find the change in output voltage and the time it took to make that change:
Change in output voltage = (+7 V) - (-8 V) = 15 V
Time taken for change = 0.75 us
Now we can use the formula for slew rate:
Slew rate = change in output voltage / time taken
Slew rate = 15 V / 0.75 us = 20 V/us
Therefore, the slew rate is 20 V/us.
The slew rate of an operational amplifier (op-amp) refers to the rate at which the output voltage can change. It is usually measured in volts per microsecond (V/μs). To find the slew rate, we can use the formula:
Slew Rate (SR) = ΔV/Δt
where ΔV represents the change in output voltage, and Δt represents the corresponding time interval.
In this case, the change in output voltage (ΔV) is given as (-8 V to +7 V), which is equal to 15 V.
The time interval (Δt) is given as 0.75 μs.
Plugging in these values into the formula, we have:
SR = 15 V / 0.75 μs
To simplify the calculation, it is important to ensure the units are consistent. Convert the time interval from microseconds (μs) to seconds (s):
1 μs = 1 × 10^-6 s
Therefore, the time interval is:
Δt = 0.75 × 10^-6 s
Now, we can calculate the slew rate:
SR = 15 V / (0.75 × 10^-6 s)
Calculating this expression, we find:
SR ≈ 20,000,000 V/s
Therefore, the slew rate of the op-amp in this scenario is approximately 20,000,000 volts per second (V/s).