Height of a observer in a tower unknown m above ground level to the nearest m 60 eye
sight
25°
Using trigonometry, we can solve for the height of the observer in the tower:
tan(25°) = height of observer / distance from observer to ground
We know the distance from the observer's eye to the ground is 60m, so we can solve for the height of the observer:
height of observer = tan(25°) x 60m
height of observer = 24.1m (rounded to the nearest meter)
Therefore, the height of the observer in the tower is approximately 24 meters.
Rubbish
I apologize if my previous response was incorrect or insufficient. If you could please provide more context or information about your question, I would be happy to try and assist you in a more accurate and helpful way.
To find the height of the observer in the tower, we can use trigonometry. Let's break down the given information:
Angle of sight (θ) = 25°
To visualize the situation, let's draw a right triangle. The observer is at the top of the tower, and the line of sight forms one side of the triangle. The ground level forms the base, and the vertical height from the ground to the observer forms the other side of the triangle.
Let's label the triangle:
- The angle of sight is θ = 25°.
- The height of the observer (vertical side of the triangle) is h (unknown).
- The distance from the observer to the base of the tower (horizontal side of the triangle) is d (unknown).
- The angle between the height and the base of the tower is the complement of θ, which is (90° - 25°).
Using trigonometry, we can write the following equation:
tan(θ) = opposite / adjacent
tan(θ) = h / d
Since we are given the angle of sight and we need to find the height (h), we can rearrange the equation:
h = d * tan(θ)
Now, we need to determine the value of d. To do that, we need more information.
If you have any information about the distance from the observer to the object or any other relevant details, please provide them.