Multiply the L.C.M of 4, 8 and 12 by its H.C.F
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First, we need to find the L.C.M of 4, 8, and 12:
Prime factorize each number:
4 = 2^2
8 = 2^3
12 = 2^2 x 3
We take the highest power of each prime factor and multiply them together to get the L.C.M:
L.C.M = 2^3 x 3 = 24
Next, we find the H.C.F of the same numbers:
Find all the factors of each number:
4 = 1, 2, 4
8 = 1, 2, 4, 8
12 = 1, 2, 3, 4, 6, 12
The common factors are 1 and 2, so the H.C.F is 2.
Finally, we multiply the L.C.M by the H.C.F:
24 x 2 = 48
Therefore, the product of the L.C.M of 4, 8 and 12 and its H.C.F is 48.
The common factors are 1 and 2, ..... AND 4 ..... so the H.C.F is ....4 ....
You are correct. I apologize for the error in my previous response. The common factors of 4, 8, and 12 are 1, 2, and 4. Therefore, their highest common factor is 4.
Thus, the product of the L.C.M of 4, 8, and 12 (which is 24) and its H.C.F (which is 4) is:
24 x 4 = 96.
To find the LCM (Least Common Multiple) of 4, 8, and 12, we need to find the smallest number that is divisible by all three numbers.
Prime factorization of 4:
4 = 2^2
Prime factorization of 8:
8 = 2^3
Prime factorization of 12:
12 = 2^2 * 3
To find the LCM, we take the highest powers of all prime factors. In this case, we have 2^3 and 3. So the LCM of 4, 8, and 12 is:
LCM = 2^3 * 3 = 24
Now, let's find the HCF (highest common factor) of 4, 8, and 12. To do this, we need to find the largest number that divides all three numbers.
Common factors of 4, 8, and 12 are 1 and 2. However, 2 is the highest common factor. So the HCF of 4, 8, and 12 is:
HCF = 2
To multiply the LCM of 4, 8, and 12 by its HCF, we simply perform the multiplication:
LCM * HCF = 24 * 2 = 48
Therefore, the result of multiplying the LCM of 4, 8, and 12 by its HCF is 48.