Find the coefficient of ๐ฅ4
in the expansion of
(1 โ 2๐ฅ)6.
A. -320
B. -240
C. 240
D. 320
Using the binomial theorem, we have:
(1 - 2๐ฅ)6 = 1 - 6(2๐ฅ) + 15(2๐ฅ)2 - 20(2๐ฅ)3 + 15(2๐ฅ)4 - 6(2๐ฅ)5 + (2๐ฅ)6
The coefficient of ๐ฅ4 is the coefficient of the term 15(2๐ฅ)4, which is 15(16) = 240. Therefore, the answer is C.
To find the coefficient of ๐ฅ^4 in the expansion of (1 - 2๐ฅ)^6, we can use the binomial theorem.
The binomial theorem states that for any positive integer n:
(๐ + ๐)^๐ = ๐ถ(๐, 0)๐^๐ + ๐ถ(๐, 1)๐^(๐โ1)๐ + ๐ถ(๐, 2)๐^(๐โ2)๐^2 + ... + ๐ถ(๐, ๐โ1)๐๐^(๐โ1) + ๐ถ(๐, ๐)๐^๐,
where ๐ถ(๐, ๐) is the binomial coefficient, which is calculated as:
๐ถ(๐, ๐) = ๐! / (๐! (๐โ๐)!)
In this case, ๐ = 6 and ๐ = 1, ๐ = -2๐ฅ. We are interested in the term with ๐ฅ^4, so ๐ = 4.
๐ถ(6, 4) = 6! / (4! (6โ4)!) = 6! / (4! 2!) = (6 * 5 * 4 * 3 * 2 * 1) / (4 * 3 * 2 * 1 * 2 * 1) = (6 * 5) / (2 * 1) = 15
So the coefficient of ๐ฅ^4 in the expansion is 15. However, we need to consider the coefficient of ๐ฅ^4 multiplied by -2^4 = -16.
Therefore, the coefficient of ๐ฅ^4 in the expansion of (1 - 2๐ฅ)^6 is -16 * 15 = -240.
Therefore, the correct answer is B. -240.