Balance the equation of the reaction between Ba(OH)2 and HOBr
Ba(OH)2 + 2 HOBr --> Ba(BrO2)2 + 2 H2O
To balance the equation for the reaction between Ba(OH)2 and HOBr, follow these steps:
Step 1: Write the unbalanced equation:
Ba(OH)2 + HOBr → BaBr2 + H2O
Step 2: Balance the Ba atoms:
The equation has one Ba atom on the left and two on the right. Add a coefficient of 1 in front of the Ba(OH)2:
Ba(OH)2 + HOBr → 1 BaBr2 + H2O
Step 3: Balance the O atoms:
The equation has two O atoms on the left and one on the right. Add a coefficient of 2 in front of the water (H2O):
Ba(OH)2 + HOBr → BaBr2 + 2 H2O
Step 4: Balance the H atoms:
The equation has four H atoms on the left and four on the right. It is already balanced.
Step 5: Balance the Br atoms:
The equation has one Br atom on the left and two on the right. Add a coefficient of 2 in front of the HOBr:
Ba(OH)2 + 2 HOBr → BaBr2 + 2 H2O
Step 6: Check that the equation is balanced:
Now, count the number of atoms on each side to ensure that they are the same:
Ba: 1 on the left, 1 on the right
O: 2 on the left, 2 on the right
H: 4 on the left, 4 on the right
Br: 1 on the left, 1 on the right
The equation is now balanced:
Ba(OH)2 + 2 HOBr → BaBr2 + 2 H2O