The ratio of girls to boys in a school is 5:3. If there are 60 boys, how many girls are in the school?

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If the ratio of girls to boys is 5:3 and we know there are 60 boys, we need to figure out how many sets of 3 boys there are in 60.

60 boys ÷ 3 boys/set = 20 sets of 3 boys

Now we can use the ratio to figure out how many girls there are.

For every 5 girls, there are 3 boys.

So for 20 sets of 3 boys, we need to multiply by 5 to get the number of girls.

20 sets of 3 boys/set × 5 girls/3 boys = 33.3 girls

We can't have a fraction of a girl, so we round to the nearest whole number.

Therefore, there are 33 girls in the school.

AAAaannndd the bot gets it wrong yet again!

5:3 = 100:60
so, there are 100 girls

I apologize for the mistake in my previous response. You are correct that the ratio of girls to boys is 5:3, which can also be represented as 100:60. If there are 60 boys, the total number of students in the school is 60 + 100 = 160. Therefore, there are 100 girls in the school. Thank you for correcting me.

To find the number of girls in the school, we need to calculate the total number of students in the school and determine the number of girls based on the given ratio.

Step 1: Calculate the total number of students in the school.
Since the ratio of girls to boys is 5:3, the total ratio of girls and boys is 5 + 3 = 8.

Step 2: Calculate the number of girls in the school.
We know that the number of boys in the school is 60. So, we can find the number of girls using the ratio:
Number of girls = (Number of girls and boys) / Total ratio * Ratio of girls = (Number of girls and boys) / 8 * 5

Substituting the given information:
Number of girls = (60 + Number of girls) / 8 * 5

Step 3: Solve for the number of girls.
Multiplying both sides of the equation by 8 gives:
8 * Number of girls = 5 * (60 + Number of girls)
8 * Number of girls = 300 + 5 * Number of girls
8 * Number of girls - 5 * Number of girls = 300
3 * Number of girls = 300
Number of girls = 300 / 3 = 100

Therefore, there are 100 girls in the school.