Convert 2.4 PPM F into molarity of fluoride. ion
To convert parts per million (PPM) to molarity, we need to know the molecular weight of the substance.
The molecular weight of fluoride ion (F-) is 18.998 g/mol.
So, to convert 2.4 PPM of fluoride (F-) into molarity, we can use the following conversion:
2.4 PPM = 2.4 mg/L
Molarity = (mg/L)/(molecular weight)
Molarity of F- = (2.4 mg/L) / 18.998 g/mol
Molarity of F- = 0.126 M
Therefore, 2.4 PPM of fluoride (F-) is equivalent to 0.126 M of fluoride ion.
To convert from parts per million (PPM) to molarity, we need to use the molar mass of the substance.
The molar mass of fluoride ion (F-) is 18.9984 g/mol.
To convert PPM to molarity, use the following equation:
Molarity (M) = PPM * molar mass / 1000
Let's now calculate the molarity of fluoride ion:
Molarity (F-) = 2.4 PPM * 18.9984 g/mol / 1000
Molarity (F-) = 0.045595 g/L
Therefore, the molarity of fluoride ion is 0.045595 M.