What is the molarity of a solution Containing 72.06 grams of BaCl2 in enough water to make 800 ml of solution.
To calculate the molarity of the solution, first calculate the number of moles of BaCl2 present in the solution:
Number of moles = Mass ÷ Molar mass
The molar mass of BaCl2 is 137.33 g/mol (137.33 = 2x(35.45) + 137.33 = 1x(137.33))
Number of moles of BaCl2 = 72.06 g ÷ 137.33 g/mol = 0.5246 moles
Next, calculate the volume of the solution in liters:
Volume of solution = 800 ml ÷ 1000 ml/L = 0.8 L
Finally, calculate the molarity of the solution:
Molarity = Number of moles ÷ Volume of solution
Molarity = 0.5246 moles ÷ 0.8 L = 0.65575 M or 0.656 M (rounded to three significant figures)
To find the molarity of a solution, you need to know the amount of solute and the volume of the solution. In this case, we have 72.06 grams of BaCl2 and the solution is made up of 800 ml of water.
1. Convert the given volume from milliliters to liters:
800 ml = 800/1000 = 0.8 liters
2. Calculate the molar mass of BaCl2 by adding the atomic masses of its elements:
Ba: 1 x 137.33 g/mol = 137.33 g/mol
Cl: 2 x 35.45 g/mol = 70.90 g/mol
Molar mass of BaCl2 = 137.33 + 70.90 = 208.23 g/mol
3. Calculate the number of moles of BaCl2 using the formula:
Moles = Mass / Molar mass
Moles = 72.06 g / 208.23 g/mol ≈ 0.34646 mol
4. Finally, calculate the molarity using the formula:
Molarity = Moles / Volume (in liters)
Molarity = 0.34646 mol / 0.8 L ≈ 0.433 M
Therefore, the molarity of the solution containing 72.06 grams of BaCl2 in enough water to make 800 ml of solution is approximately 0.433 M.