C8H16+ 120, -> 8 CO, +8 H,° determine the mole ratios
The balanced equation is:
C8H16 + 120 O2 -> 8 CO2 + 8 H2O
The mole ratios are:
1 mole of C8H16 reacts with 15 moles of O2
8 moles of CO2 are produced
8 moles of H2O are produced
Therefore, the mole ratio of C8H16 to CO2 is 1:8 and the mole ratio of C8H16 to H2O is also 1:8.
The balanced chemical equation you provided is:
C8H16 + 120 O2 -> 8 CO2 + 8 H2O
To determine the mole ratios based on this balanced equation, we look at the coefficients in front of each compound or element.
For C8H16 (octane), the coefficient is 1. Therefore, the mole ratio of C8H16 is 1:1.
For O2 (oxygen), the coefficient is 120. Therefore, the mole ratio of O2 is 120:0 (since it is completely consumed in the reaction).
For CO2 (carbon dioxide), the coefficient is 8. Therefore, the mole ratio of CO2 is 8:0 (since it is completely produced in the reaction).
For H2O (water), the coefficient is 8. Therefore, the mole ratio of H2O is 8:0 (since it is completely produced in the reaction).
Based on these coefficients, the mole ratios in the balanced equation are as follows:
C8H16 : O2 = 1:120
C8H16 : CO2 = 1:8
C8H16 : H2O = 1:8