A rectangular field is two
times as long as it is wide. If the perimeter of the field is 180
yards, what are the field's dimensions?
Let's call the width of the field "x". Then, according to the problem, the length of the field is 2 times the width, or 2x.
The formula for the perimeter of a rectangle is:
perimeter = 2(length + width)
So, using the values we just found, we can write:
180 = 2(2x + x)
Simplifying the right side:
180 = 2(3x)
180 = 6x
Dividing both sides by 6:
30 = x
So the width of the field is 30 yards.
Using the fact that the length is 2 times the width, we can find the length:
length = 2x = 2(30) = 60
So the dimensions of the field are 30 yards by 60 yards.
Let's assume that the width of the field is 'x' yards.
Since the length is two times the width, the length would be '2x' yards.
The perimeter of a rectangle is given by the formula: P = 2(length + width).
Substituting the given values, we have:
180 = 2(2x + x)
Simplifying the equation:
180 = 2(3x)
180 = 6x
Divide both sides by 6 to solve for 'x':
x = 30
So, the width of the field is 30 yards.
Since the length is two times the width:
Length = 2x = 2(30) = 60 yards.
Therefore, the dimensions of the field are 30 yards (width) and 60 yards (length).