8.00 gram of calcium chloride. Is dissolved in 1.000kg of Water. How many moles of calcium chloride are in solution? How many moons of water? Are present.
To calculate the number of moles of calcium chloride, we need to use its molar mass. The molar mass of calcium chloride is:
CaCl2 = 1 x 40.08 g/mol (for calcium) + 2 x 35.45 g/mol (for chlorine) = 110.98 g/mol
So, the number of moles of calcium chloride in 8.00 g is:
n = m/M = 8.00 g /110.98 g/mol = 0.072 mol
To calculate the number of moles of water, we can use its molar mass, which is:
H2O = 2 x 1.01 g/mol (for hydrogen) + 1 x 16.00 g/mol (for oxygen) = 18.02 g/mol
The mass of 1.000 kg of water is:
m = 1.000 kg x 1000 g/kg = 1000 g
So, the number of moles of water is:
n = m/M = 1000 g / 18.02 g/mol = 55.49 mol
Therefore, there are 0.072 moles of calcium chloride and 55.49 moles of water present in the solution.
To calculate the number of moles of calcium chloride in the solution, we need to use the formula:
Moles = Mass ÷ Molar mass
The molar mass of calcium chloride (CaCl2) is the sum of the atomic masses of calcium (Ca) and chlorine (Cl). The atomic masses can be found on the periodic table.
The atomic mass of calcium (Ca) is 40.08 g/mol.
The atomic mass of chlorine (Cl) is 35.45 g/mol.
Therefore, the molar mass of calcium chloride (CaCl2) is:
Molar mass = (1 × atomic mass of calcium) + (2 × atomic mass of chlorine)
= (1 × 40.08) + (2 × 35.45)
= 110.98 g/mol
Now let's calculate the number of moles of calcium chloride in the solution:
Moles of calcium chloride = 8.00 g ÷ 110.98 g/mol
Moles of calcium chloride = 0.0719 mol (rounded to four decimal places)
To calculate the number of moles of water in the solution, we need to use the formula:
Moles = Mass ÷ Molar mass
The molar mass of water (H2O) is the sum of the atomic masses of hydrogen (H) and oxygen (O). The atomic masses can be found on the periodic table.
The atomic mass of hydrogen (H) is 1.008 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.
Therefore, the molar mass of water (H2O) is:
Molar mass = (2 × atomic mass of hydrogen) + (1 × atomic mass of oxygen)
= (2 × 1.008) + (1 × 16.00)
= 18.02 g/mol
Now let's calculate the number of moles of water in the solution:
Moles of water = 1.000 kg × 1000 g/kg ÷ 18.02 g/mol
Moles of water = 55.51 mol (rounded to two decimal places)
So, in the given solution, there are approximately 0.0719 moles of calcium chloride and 55.51 moles of water.