Divide 15x5 - 3x3 - 9x2 by -3x2

We can use long division to divide 15x5 - 3x3 - 9x2 by -3x2:

```
-5x3 + 3x + (-3/ x)
______________________
-3x2 | 15x5 - 3x3 - 9x2 + 0x + 0x
- (15x3 - 0x2 + 0x)
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- 3x2 - 9x2 + 0x
- (-3x2 + 0x)
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- 9x2 + 0x
```

Therefore, the quotient is -5x3 + 3x - (3/x), and the remainder is -9x2 + 0x.

To divide 15x^5 - 3x^3 - 9x^2 by -3x^2, we can follow these steps:

Step 1: Divide the coefficient of the first term by the coefficient of the divisor.
- The coefficient of 15x^5 is 15, and the coefficient of -3x^2 is -3.
- 15 divided by -3 is -5.
- So, the first term of the quotient is -5x^3.

Step 2: Divide each term of the dividend by the divisor.
- The original division problem was (15x^5 - 3x^3 - 9x^2) / (-3x^2).
- Divide the first term, 15x^5, by -3x^2.
- 15x^5 / -3x^2 = -5x^3

- Divide the second term, -3x^3, by -3x^2.
- -3x^3 / -3x^2 = x

- Divide the third term, -9x^2, by -3x^2.
- -9x^2 / -3x^2 = 3

The quotient of 15x^5 - 3x^3 - 9x^2 divided by -3x^2 is -5x^3 + x + 3.