mass of 3.00mol of selenium oxybromide
To find the mass of 3.00 mol of selenium oxybromide, we need to know the molecular formula and molar mass of the compound.
The molecular formula for selenium oxybromide is SeOBr2.
To calculate the molar mass, we need to add up the atomic masses of selenium (Se), oxygen (O), and two bromine (Br) atoms:
Mass of Se = 78.96 g/mol
Mass of O = 15.99 g/mol
Mass of 2 Br = 2 x 79.90 g/mol = 159.80 g/mol
Molar mass of SeOBr2 = 78.96 g/mol + 15.99 g/mol + 159.80 g/mol = 254.75 g/mol
Now we can use the molar mass to find the mass of 3.00 mol of SeOBr2:
Mass = 3.00 mol x 254.75 g/mol = 764.25 g
Therefore, the mass of 3.00 mol of selenium oxybromide is 764.25 g.
To determine the mass of 3.00 mol of selenium oxybromide, you need to know the molar mass of the compound. The molar mass is the sum of the atomic masses of each element in the compound, multiplied by the number of atoms of that element.
Let's break down the compound, selenium oxybromide (SeOBr2), and calculate its molar mass:
Selenium (Se) has an atomic mass of 78.96 g/mol.
Oxygen (O) has an atomic mass of 16.00 g/mol.
Bromine (Br) has an atomic mass of 79.90 g/mol.
Since selenium oxybromide (SeOBr2) has 1 selenium atom, 1 oxygen atom, and 2 bromine atoms, we can calculate its molar mass as follows:
Molar mass of Se = 78.96 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Br = 79.90 g/mol
Molar mass of SeOBr2 = (78.96 g/mol) + (16.00 g/mol) + 2*(79.90 g/mol)
= 78.96 g/mol + 16.00 g/mol + 159.80 g/mol
= 254.76 g/mol
Now, to find the mass of 3.00 mol of selenium oxybromide, you can use the formula:
Mass = Number of moles × Molar mass
Mass of 3.00 mol of selenium oxybromide = 3.00 mol × 254.76 g/mol
= 764.28 g
Therefore, the mass of 3.00 mol of selenium oxybromide is 764.28 grams.